2x^2+40=-x^2-56

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Solution for 2x^2+40=-x^2-56 equation: 



2x^2+40=-x^2-56

We move all terms to the left:

2x^2+40-(-x^2-56)=0

We get rid of parentheses

2x^2+x^2+56+40=0

We add all the numbers together, and all the variables

3x^2+96=0

a = 3; b = 0; c = +96;
Δ = b2-4ac
Δ = 02-4·3·96
Δ = -1152
Delta is less than zero, so there is no solution for the equation

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